Integrand size = 25, antiderivative size = 188 \[ \int (e \cos (c+d x))^{7/2} (a+b \sin (c+d x))^2 \, dx=-\frac {26 a b (e \cos (c+d x))^{9/2}}{99 d e}+\frac {10 \left (11 a^2+2 b^2\right ) e^4 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{231 d \sqrt {e \cos (c+d x)}}+\frac {10 \left (11 a^2+2 b^2\right ) e^3 \sqrt {e \cos (c+d x)} \sin (c+d x)}{231 d}+\frac {2 \left (11 a^2+2 b^2\right ) e (e \cos (c+d x))^{5/2} \sin (c+d x)}{77 d}-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e} \]
-26/99*a*b*(e*cos(d*x+c))^(9/2)/d/e+2/77*(11*a^2+2*b^2)*e*(e*cos(d*x+c))^( 5/2)*sin(d*x+c)/d-2/11*b*(e*cos(d*x+c))^(9/2)*(a+b*sin(d*x+c))/d/e+10/231* (11*a^2+2*b^2)*e^4*(cos(1/2*d*x+1/2*c)^2)^(1/2)/cos(1/2*d*x+1/2*c)*Ellipti cF(sin(1/2*d*x+1/2*c),2^(1/2))*cos(d*x+c)^(1/2)/d/(e*cos(d*x+c))^(1/2)+10/ 231*(11*a^2+2*b^2)*e^3*sin(d*x+c)*(e*cos(d*x+c))^(1/2)/d
Time = 1.73 (sec) , antiderivative size = 160, normalized size of antiderivative = 0.85 \[ \int (e \cos (c+d x))^{7/2} (a+b \sin (c+d x))^2 \, dx=\frac {(e \cos (c+d x))^{7/2} \left (-154 a b \sqrt {\cos (c+d x)}+40 \left (11 a^2+2 b^2\right ) \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )+\frac {1}{6} \sqrt {\cos (c+d x)} \left (6 \left (572 a^2+41 b^2\right ) \sin (c+d x)-14 b \cos (4 (c+d x)) (22 a+9 b \sin (c+d x))+8 \cos (2 (c+d x)) \left (-154 a b+9 \left (11 a^2-5 b^2\right ) \sin (c+d x)\right )\right )\right )}{924 d \cos ^{\frac {7}{2}}(c+d x)} \]
((e*Cos[c + d*x])^(7/2)*(-154*a*b*Sqrt[Cos[c + d*x]] + 40*(11*a^2 + 2*b^2) *EllipticF[(c + d*x)/2, 2] + (Sqrt[Cos[c + d*x]]*(6*(572*a^2 + 41*b^2)*Sin [c + d*x] - 14*b*Cos[4*(c + d*x)]*(22*a + 9*b*Sin[c + d*x]) + 8*Cos[2*(c + d*x)]*(-154*a*b + 9*(11*a^2 - 5*b^2)*Sin[c + d*x])))/6))/(924*d*Cos[c + d *x]^(7/2))
Time = 0.79 (sec) , antiderivative size = 179, normalized size of antiderivative = 0.95, number of steps used = 13, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.520, Rules used = {3042, 3171, 27, 3042, 3148, 3042, 3115, 3042, 3115, 3042, 3121, 3042, 3120}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int (e \cos (c+d x))^{7/2} (a+b \sin (c+d x))^2 \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int (e \cos (c+d x))^{7/2} (a+b \sin (c+d x))^2dx\) |
| \(\Big \downarrow \) 3171 |
| \(\displaystyle \frac {2}{11} \int \frac {1}{2} (e \cos (c+d x))^{7/2} \left (11 a^2+13 b \sin (c+d x) a+2 b^2\right )dx-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {1}{11} \int (e \cos (c+d x))^{7/2} \left (11 a^2+13 b \sin (c+d x) a+2 b^2\right )dx-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {1}{11} \int (e \cos (c+d x))^{7/2} \left (11 a^2+13 b \sin (c+d x) a+2 b^2\right )dx-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
| \(\Big \downarrow \) 3148 |
| \(\displaystyle \frac {1}{11} \left (\left (11 a^2+2 b^2\right ) \int (e \cos (c+d x))^{7/2}dx-\frac {26 a b (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {1}{11} \left (\left (11 a^2+2 b^2\right ) \int \left (e \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{7/2}dx-\frac {26 a b (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
| \(\Big \downarrow \) 3115 |
| \(\displaystyle \frac {1}{11} \left (\left (11 a^2+2 b^2\right ) \left (\frac {5}{7} e^2 \int (e \cos (c+d x))^{3/2}dx+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {26 a b (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {1}{11} \left (\left (11 a^2+2 b^2\right ) \left (\frac {5}{7} e^2 \int \left (e \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{3/2}dx+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {26 a b (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
| \(\Big \downarrow \) 3115 |
| \(\displaystyle \frac {1}{11} \left (\left (11 a^2+2 b^2\right ) \left (\frac {5}{7} e^2 \left (\frac {1}{3} e^2 \int \frac {1}{\sqrt {e \cos (c+d x)}}dx+\frac {2 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{3 d}\right )+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {26 a b (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {1}{11} \left (\left (11 a^2+2 b^2\right ) \left (\frac {5}{7} e^2 \left (\frac {1}{3} e^2 \int \frac {1}{\sqrt {e \sin \left (c+d x+\frac {\pi }{2}\right )}}dx+\frac {2 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{3 d}\right )+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {26 a b (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
| \(\Big \downarrow \) 3121 |
| \(\displaystyle \frac {1}{11} \left (\left (11 a^2+2 b^2\right ) \left (\frac {5}{7} e^2 \left (\frac {e^2 \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\cos (c+d x)}}dx}{3 \sqrt {e \cos (c+d x)}}+\frac {2 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{3 d}\right )+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {26 a b (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {1}{11} \left (\left (11 a^2+2 b^2\right ) \left (\frac {5}{7} e^2 \left (\frac {e^2 \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{3 \sqrt {e \cos (c+d x)}}+\frac {2 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{3 d}\right )+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {26 a b (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
| \(\Big \downarrow \) 3120 |
| \(\displaystyle \frac {1}{11} \left (\left (11 a^2+2 b^2\right ) \left (\frac {5}{7} e^2 \left (\frac {2 e^2 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{3 d \sqrt {e \cos (c+d x)}}+\frac {2 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{3 d}\right )+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {26 a b (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 b (e \cos (c+d x))^{9/2} (a+b \sin (c+d x))}{11 d e}\) |
(-2*b*(e*Cos[c + d*x])^(9/2)*(a + b*Sin[c + d*x]))/(11*d*e) + ((-26*a*b*(e *Cos[c + d*x])^(9/2))/(9*d*e) + (11*a^2 + 2*b^2)*((2*e*(e*Cos[c + d*x])^(5 /2)*Sin[c + d*x])/(7*d) + (5*e^2*((2*e^2*Sqrt[Cos[c + d*x]]*EllipticF[(c + d*x)/2, 2])/(3*d*Sqrt[e*Cos[c + d*x]]) + (2*e*Sqrt[e*Cos[c + d*x]]*Sin[c + d*x])/(3*d)))/7))/11
3.6.47.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-b)*Cos[c + d* x]*((b*Sin[c + d*x])^(n - 1)/(d*n)), x] + Simp[b^2*((n - 1)/n) Int[(b*Sin [c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && IntegerQ[ 2*n]
Int[1/Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticF[(1/2 )*(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
Int[((b_)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*Sin[c + d*x]) ^n/Sin[c + d*x]^n Int[Sin[c + d*x]^n, x], x] /; FreeQ[{b, c, d}, x] && Lt Q[-1, n, 1] && IntegerQ[2*n]
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)]), x_Symbol] :> Simp[(-b)*((g*Cos[e + f*x])^(p + 1)/(f*g*(p + 1))), x] + Simp[a Int[(g*Cos[e + f*x])^p, x], x] /; FreeQ[{a, b, e, f, g, p}, x] && (IntegerQ[2*p] || NeQ[a^2 - b^2, 0])
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x _)])^(m_), x_Symbol] :> Simp[(-b)*(g*Cos[e + f*x])^(p + 1)*((a + b*Sin[e + f*x])^(m - 1)/(f*g*(m + p))), x] + Simp[1/(m + p) Int[(g*Cos[e + f*x])^p* (a + b*Sin[e + f*x])^(m - 2)*(b^2*(m - 1) + a^2*(m + p) + a*b*(2*m + p - 1) *Sin[e + f*x]), x], x] /; FreeQ[{a, b, e, f, g, p}, x] && NeQ[a^2 - b^2, 0] && GtQ[m, 1] && NeQ[m + p, 0] && (IntegersQ[2*m, 2*p] || IntegerQ[m])
Leaf count of result is larger than twice the leaf count of optimal. \(471\) vs. \(2(192)=384\).
Time = 16.84 (sec) , antiderivative size = 472, normalized size of antiderivative = 2.51
| method | result | size |
| parts | \(-\frac {2 a^{2} \sqrt {e \left (2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}\, e^{4} \left (48 \left (\cos ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-120 \left (\cos ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+128 \left (\cos ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-72 \left (\cos ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+5 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {-2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+1}\, F\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )+16 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{21 \sqrt {-e \left (2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )}\, \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {e \left (2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right )}\, d}+\frac {4 b^{2} \sqrt {e \left (2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}\, e^{4} \left (672 \left (\cos ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-2352 \left (\cos ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+3312 \left (\cos ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-2400 \left (\cos ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+922 \left (\cos ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-159 \left (\cos ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-5 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {-2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+1}\, F\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )+5 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{231 \sqrt {-e \left (2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )}\, \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {e \left (2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right )}\, d}-\frac {4 a b \left (e \cos \left (d x +c \right )\right )^{\frac {9}{2}}}{9 d e}\) | \(472\) |
| default | \(\frac {2 e^{4} \left (4032 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}-10080 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}+4928 \left (\sin ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b -1584 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2}+9792 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}-12320 \left (\sin ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b +2376 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2}-4608 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}+12320 \left (\sin ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b -1848 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2}+924 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}-6160 \left (\sin ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b +528 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2}-30 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}-165 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, F\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) a^{2}-30 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, F\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) b^{2}+1540 a b \left (\sin ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-154 \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) a b \right )}{693 \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {-2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +e}\, d}\) | \(473\) |
-2/21*a^2*(e*(2*cos(1/2*d*x+1/2*c)^2-1)*sin(1/2*d*x+1/2*c)^2)^(1/2)*e^4*(4 8*cos(1/2*d*x+1/2*c)^9-120*cos(1/2*d*x+1/2*c)^7+128*cos(1/2*d*x+1/2*c)^5-7 2*cos(1/2*d*x+1/2*c)^3+5*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*cos(1/2*d*x+1/2* c)^2+1)^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),2^(1/2))+16*cos(1/2*d*x+1/2*c)) /(-e*(2*sin(1/2*d*x+1/2*c)^4-sin(1/2*d*x+1/2*c)^2))^(1/2)/sin(1/2*d*x+1/2* c)/(e*(2*cos(1/2*d*x+1/2*c)^2-1))^(1/2)/d+4/231*b^2*(e*(2*cos(1/2*d*x+1/2* c)^2-1)*sin(1/2*d*x+1/2*c)^2)^(1/2)*e^4*(672*cos(1/2*d*x+1/2*c)^13-2352*co s(1/2*d*x+1/2*c)^11+3312*cos(1/2*d*x+1/2*c)^9-2400*cos(1/2*d*x+1/2*c)^7+92 2*cos(1/2*d*x+1/2*c)^5-159*cos(1/2*d*x+1/2*c)^3-5*(sin(1/2*d*x+1/2*c)^2)^( 1/2)*(-2*cos(1/2*d*x+1/2*c)^2+1)^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),2^(1/2 ))+5*cos(1/2*d*x+1/2*c))/(-e*(2*sin(1/2*d*x+1/2*c)^4-sin(1/2*d*x+1/2*c)^2) )^(1/2)/sin(1/2*d*x+1/2*c)/(e*(2*cos(1/2*d*x+1/2*c)^2-1))^(1/2)/d-4/9*a*b* (e*cos(d*x+c))^(9/2)/d/e
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.11 (sec) , antiderivative size = 173, normalized size of antiderivative = 0.92 \[ \int (e \cos (c+d x))^{7/2} (a+b \sin (c+d x))^2 \, dx=\frac {-15 i \, \sqrt {2} {\left (11 \, a^{2} + 2 \, b^{2}\right )} e^{\frac {7}{2}} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right ) + 15 i \, \sqrt {2} {\left (11 \, a^{2} + 2 \, b^{2}\right )} e^{\frac {7}{2}} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right ) - 2 \, {\left (154 \, a b e^{3} \cos \left (d x + c\right )^{4} + 3 \, {\left (21 \, b^{2} e^{3} \cos \left (d x + c\right )^{4} - 3 \, {\left (11 \, a^{2} + 2 \, b^{2}\right )} e^{3} \cos \left (d x + c\right )^{2} - 5 \, {\left (11 \, a^{2} + 2 \, b^{2}\right )} e^{3}\right )} \sin \left (d x + c\right )\right )} \sqrt {e \cos \left (d x + c\right )}}{693 \, d} \]
1/693*(-15*I*sqrt(2)*(11*a^2 + 2*b^2)*e^(7/2)*weierstrassPInverse(-4, 0, c os(d*x + c) + I*sin(d*x + c)) + 15*I*sqrt(2)*(11*a^2 + 2*b^2)*e^(7/2)*weie rstrassPInverse(-4, 0, cos(d*x + c) - I*sin(d*x + c)) - 2*(154*a*b*e^3*cos (d*x + c)^4 + 3*(21*b^2*e^3*cos(d*x + c)^4 - 3*(11*a^2 + 2*b^2)*e^3*cos(d* x + c)^2 - 5*(11*a^2 + 2*b^2)*e^3)*sin(d*x + c))*sqrt(e*cos(d*x + c)))/d
Timed out. \[ \int (e \cos (c+d x))^{7/2} (a+b \sin (c+d x))^2 \, dx=\text {Timed out} \]
\[ \int (e \cos (c+d x))^{7/2} (a+b \sin (c+d x))^2 \, dx=\int { \left (e \cos \left (d x + c\right )\right )^{\frac {7}{2}} {\left (b \sin \left (d x + c\right ) + a\right )}^{2} \,d x } \]
\[ \int (e \cos (c+d x))^{7/2} (a+b \sin (c+d x))^2 \, dx=\int { \left (e \cos \left (d x + c\right )\right )^{\frac {7}{2}} {\left (b \sin \left (d x + c\right ) + a\right )}^{2} \,d x } \]
Timed out. \[ \int (e \cos (c+d x))^{7/2} (a+b \sin (c+d x))^2 \, dx=\int {\left (e\,\cos \left (c+d\,x\right )\right )}^{7/2}\,{\left (a+b\,\sin \left (c+d\,x\right )\right )}^2 \,d x \]